8x^2-10x=432

Solution for 8x^2-10x=432 equation:

8x^2-10x=432

We move all terms to the left:

8x^2-10x-(432)=0

a = 8; b = -10; c = -432;
Δ = b2-4ac
Δ = -102-4·8·(-432)
Δ = 13924
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{13924}=118$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-118}{2*8}=\frac{-108}{16}
=-6+3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+118}{2*8}=\frac{128}{16}
=8
$